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How to Solve Evaluate the Bracket Pairs of a String Problem
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Medium#1807
LeetCode ProblemEvaluate the Bracket Pairs of a String
You are given a string s that contains some bracket pairs, with each pair containing a non-empty key. You know the values of a wide range of keys. This is represented by a 2D string array knowledge where each knowledge[i] = [keyi, valuei] indicates that key keyi has a value of valuei. You are tasked to evaluate all of the bracket pairs. When you evaluate a bracket pair that contains some key keyi, you will: Each key will appear at most once in your knowledge. There will not be any nested brackets in s. Return the resulting string after evaluating all of the bracket pairs.
ArrayHash TableString
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Problem Breakdown
Understanding the Evaluate the Bracket Pairs of a String Problem
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Problem Statement
You are given a string s that contains some bracket pairs, with each pair containing a non-empty key. You know the values of a wide range of keys. This is represented by a 2D string array knowledge where each knowledge[i] = [keyi, valuei] indicates that key keyi has a value of valuei. You are tasked to evaluate all of the bracket pairs. When you evaluate a bracket pair that contains some key keyi, you will: Each key will appear at most once in your knowledge. There will not be any nested brackets in s. Return the resulting string after evaluating all of the bracket pairs.
MediumProblem #1807
LeetCodeEvaluate the Bracket Pairs of a String
Related Topics
ArrayHash TableString
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Examples
# Example 1
Input
s = "(name)is(age)yearsold", knowledge = [["name","bob"],["age","two"]]
Output
"bobistwoyearsold"
# Example 2
Input
s = "hi(name)", knowledge = [["a","b"]]
Output
"hi?"
# Example 3
Input
s = "(a)(a)(a)aaa", knowledge = [["a","yes"]]
Output
"yesyesyesaaa"
Constraints
1 <= s.length <= 105
0 <= knowledge.length <= 105
knowledge[i].length == 2
1 <= keyi.length, valuei.length <= 10
s consists of lowercase English letters and round brackets '(' and ')'.
Every open bracket '(' in s will have a corresponding close bracket ')'.
The key in each bracket pair of s will be non-empty.
There will not be any nested bracket pairs in s.
keyi and valuei consist of lowercase English letters.
Each keyi in knowledge is unique.
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Solve Evaluate the Bracket Pairs of a String — You are given a string s that contains some bracket pairs, with each pair contai...
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