How to Solve Serialize and Deserialize Binary Tree Problem
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Serialize and Deserialize Binary Tree
Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment. Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure. Clarification: The input/output format is the same as how LeetCode serializes a binary tree. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.
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Understanding the Serialize and Deserialize Binary Tree Problem
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Problem Statement
Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment. Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure. Clarification: The input/output format is the same as how LeetCode serializes a binary tree. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.
Serialize and Deserialize Binary Tree
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Examples
# Example 1
root = [1,2,3,null,null,4,5]
[1,2,3,null,null,4,5]
# Example 2
root = []
[]
Constraints
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Solve Serialize and Deserialize Binary Tree — Serialization is the process of converting a data structure or object into a seq...
Here's the optimal approach using String:
Time: O(n) | Space: O(n)
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