Practice Compare Strings by Frequency of the Smallest Character
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Compare Strings by Frequency of the Smallest Character
Let the function f(s) be the frequency of the lexicographically smallest character in a non-empty string s. For example, if s = "dcce" then f(s) = 2 because the lexicographically smallest character is 'c', which has a frequency of 2. You are given an array of strings words and another array of query strings queries. For each query queries[i], count the number of words in words such that f(queries[i]) < f(W) for each W in words. Return an integer array answer, where each answer[i] is the answer to the ith query.
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Understanding the Compare Strings by Frequency of the Smallest Character Problem
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Problem Statement
Let the function f(s) be the frequency of the lexicographically smallest character in a non-empty string s. For example, if s = "dcce" then f(s) = 2 because the lexicographically smallest character is 'c', which has a frequency of 2. You are given an array of strings words and another array of query strings queries. For each query queries[i], count the number of words in words such that f(queries[i]) < f(W) for each W in words. Return an integer array answer, where each answer[i] is the answer to the ith query.
Source: Compare Strings by Frequency of the Smallest Character on LeetCode. Use the original task for its coding environment and submissions.
Compare Strings by Frequency of the Smallest Character
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Examples
# Example 1
queries = ["cbd"], words = ["zaaaz"]
[1]
# Example 2
queries = ["bbb","cc"], words = ["a","aa","aaa","aaaa"]
[1,2]
Constraints
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