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How to Solve Partition Array Into Three Parts With Equal Sum Problem
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Easy#1013
LeetCode ProblemPartition Array Into Three Parts With Equal Sum
Given an array of integers arr, return true if we can partition the array into three non-empty parts with equal sums. Formally, we can partition the array if we can find indexes i + 1 < j with (arr[0] + arr[1] + ... + arr[i] == arr[i + 1] + arr[i + 2] + ... + arr[j - 1] == arr[j] + arr[j + 1] + ... + arr[arr.length - 1])
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Problem Breakdown
Understanding the Partition Array Into Three Parts With Equal Sum Problem
Let's break down this LeetCode problem and understand what makes it challenging in interview settings.
Problem Statement
Given an array of integers arr, return true if we can partition the array into three non-empty parts with equal sums. Formally, we can partition the array if we can find indexes i + 1 < j with (arr[0] + arr[1] + ... + arr[i] == arr[i + 1] + arr[i + 2] + ... + arr[j - 1] == arr[j] + arr[j + 1] + ... + arr[arr.length - 1])
Examples
# Example 1
Input
arr = [0,2,1,-6,6,-7,9,1,2,0,1]
Output
true
# Example 2
Input
arr = [0,2,1,-6,6,7,9,-1,2,0,1]
Output
false
# Example 3
Input
arr = [3,3,6,5,-2,2,5,1,-9,4]
Output
true
Constraints
3 <= arr.length <= 5 * 104
-104 <= arr[i] <= 104
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Solve Partition Array Into Three Parts With Equal Sum — Given an array of integers arr, return true if we can partition the array into t...
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def solve(input):
# Optimal O(n) solution
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Time: O(n) | Space: O(n)
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